8x^2-x=2x+2

Solution for 8x^2-x=2x+2 equation:

8x^2-x=2x+2

We move all terms to the left:

8x^2-x-(2x+2)=0

We add all the numbers together, and all the variables

8x^2-1x-(2x+2)=0

We get rid of parentheses

8x^2-1x-2x-2=0

We add all the numbers together, and all the variables

8x^2-3x-2=0

a = 8; b = -3; c = -2;
Δ = b2-4ac
Δ = -32-4·8·(-2)
Δ = 73
The delta value is higher than zero, so the equation has two solutions
We use following formulas to calculate our solutions:
$x_{1}=\frac{-b-\sqrt{\Delta}}{2a}$
$x_{2}=\frac{-b+\sqrt{\Delta}}{2a}$

$x_{1}=\frac{-b-\sqrt{\Delta}}{2a}=\frac{-(-3)-\sqrt{73}}{2*8}=\frac{3-\sqrt{73}}{16}
$
$x_{2}=\frac{-b+\sqrt{\Delta}}{2a}=\frac{-(-3)+\sqrt{73}}{2*8}=\frac{3+\sqrt{73}}{16}
$